2.1295=0.014X^2-0.3748x+3.2463

Solution for 2.1295=0.014X^2-0.3748x+3.2463 equation:

2.1295=0.014X^2-0.3748X+3.2463

We move all terms to the left:

2.1295-(0.014X^2-0.3748X+3.2463)=0

We get rid of parentheses

-0.014X^2+0.3748X-3.2463+2.1295=0

We add all the numbers together, and all the variables

-0.014X^2+0.3748X-1.1168=0

a = -0.014; b = 0.3748; c = -1.1168;
Δ = b2-4ac
Δ = 0.37482-4·(-0.014)·(-1.1168)
Δ = 0.07793424
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0.3748)-\sqrt{0.07793424}}{2*-0.014}=\frac{-0.3748-\sqrt{0.07793424}}{-0.028}
$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0.3748)+\sqrt{0.07793424}}{2*-0.014}=\frac{-0.3748+\sqrt{0.07793424}}{-0.028}
$